Third Customer Purchase

SQL practice question · Medium · Window Functions · Uber

ledger_entries has one row per ride payment (user_id, transaction_date, amount). For each user with at least three transactions, return their third transaction in chronological order; if two transactions share a date, the smaller amount counts first. Output columns: user_id, third_transaction_date, amount. Order by user_id ascending.

Table: ledger_entries

Schema of ledger_entries
Column	Type
user_id	INTEGER
transaction_date	DATE
amount	REAL

Schema of ledger_entries

Column

Type

user_id

INTEGER

transaction_date

DATE

amount

REAL

Sample rows of ledger_entries
user_id	transaction_date	amount
1	2026-01-01	10
1	2026-01-03	20
1	2026-01-05	30
1	2026-01-08	40
2	2026-02-01	15
2	2026-02-04	25
2	2026-02-06	35

Sample rows of ledger_entries

user_id

transaction_date

amount

2026-01-01

2026-01-03

2026-01-05

2026-01-08

2026-02-01

2026-02-04

2026-02-06

Expected output on the sample data
user_id	third_transaction_date	amount
1	2026-01-05	30
2	2026-02-06	35

Expected output on the sample data

user_id

third_transaction_date

amount

2026-01-05

2026-02-06

Solve it in the live editor on this page — run on sample data, then submit against hidden tests.

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